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Pressurization question (aircraft systems HW

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Old 02-10-2013, 09:59 PM
  #1  
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Default Pressurization question (aircraft systems HW

I have no idea what to do about this, my proffessor never gave me any tips on how to solve this, it isn't even in our systems book!

A cabin door which has a width of 26" and a height of 70" will produce a force on the structure of ____Lbs when the cabin differential pressure is at 7.3p.s.i

I understand the cabind pressure differential but no clue about the resultant force.
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Old 02-10-2013, 10:19 PM
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26x70x7.3=total force in pounds

or total square inch area times PSI
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Old 02-10-2013, 10:47 PM
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Originally Posted by jungle
26x70x7.3=total force in pounds

or total square inch area times PSI
yeaaaaaaa i just figured it out....Read the portion on differential pressure a little more and came up with the answer....silly me for not thinking hard enough
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Old 02-10-2013, 11:23 PM
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The real lesson to learn there is why a pilot should always insure that cabin pressure equals outside air pressure prior to opening the door.

For example, a 0.1 psi difference when the flight attendant opens the door: 26*70*0.1=182 pounds of force. If she/he as a good grip on the handle, she/he will end up face down on the ramp.

Just food for thought.
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Old 02-11-2013, 12:43 AM
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Originally Posted by FlyJSH

For example, a 0.1 psi difference when the flight attendant opens the door: 26*70*0.1=182 pounds of force. If she/he as a good grip on the handle, she/he will end up face down on the ramp.

Just food for thought.
That's why all good systems land 100' below the airport elevation!

On behalf of our young "Hawker driving" scholar, thanks Jungle! Kids these days.
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Old 02-11-2013, 08:33 AM
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Originally Posted by HSLD
That's why all good systems land 100' below the airport elevation!

Interesting, Never knew that.
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Old 02-11-2013, 01:32 PM
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Originally Posted by HSLD
That's why all good systems land 100' below the airport elevation!

On behalf of our young "Hawker driving" scholar, thanks Jungle! Kids these days.
HSLD, I think you have the explanation backwards on this one. Many pressurization systems land 100' below field elevation to maximize smoothness in the pressurization schedule, but it leaves the airplane pressurized to a slight extent. Most aircraft that I have flown then slowly dump this residual pressurization by a weight on wheels switch.

To avoid landing pressurized, the system would pressurize to 100' ABOVE airport elevation.

Joe
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Old 02-11-2013, 02:47 PM
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Originally Posted by joepilot
HSLD, I think you have the explanation backwards on this one. Many pressurization systems land 100' below field elevation to maximize smoothness in the pressurization schedule, but it leaves the airplane pressurized to a slight extent. Most aircraft that I have flown then slowly dump this residual pressurization by a weight on wheels switch.

To avoid landing pressurized, the system would pressurize to 100' ABOVE airport elevation.

Joe
Doh! You're right, I meant takes off below field elevation! Landing pressurized would make it tough to get the doors open in a hurry!
Sorry for the typo.
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